SAT® Math: Hard Questions EASY Hacks

SAT® Math: Hard Questions EASY Hacks

SAT® Math: Hard Questions EASY Hacks

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47 Responses to “SAT® Math: Hard Questions EASY Hacks”

  1. Jayden Lin says:

    Should I be worried if I can’t understand 19 when I haven’t been through trigonometry yet?

  2. Bhadka Aspirant says:

    For indians its 6th standard

  3. qwertyuiop 0110 says:

    what a joke. The SAT questions are easy, 15 year old students from other parts of the world(for instance, Britain or India) can do this without difficulty. Its more of test taking technique than knowledge of the subject tested(typical American education system).

  4. Edu 10th says:

    Would you recommend buying the ACT math book to study for SAT Math?

  5. Amr Obaia says:

    Very useful tricks

  6. Mays Faisal says:

    you made the questions look way harder than it should

  7. Mohammad Nasser says:

    Good luck for tomorrow

  8. Geg Zakaryan says:

    The first one has a much easier solution (which is mentioned for half a second on the video):

    Just make the bases the same FROM THE BEGINNING. So 8^x/2^x becomes 2^3x/2^y and then use the rule shown, so it becomes 2^(3x-y) and you can see that you have 3x-y=12, so the answer is 2¹²

  9. TableCat says:

    The exponent question was done poorly in my opinion. Reducing 8^x/2^y is 2^3x/2^y, and by knowing basic exponent rules you the exponent of 2 equal to the quotient is 3x-y, which we know is 12

  10. chloé bourgeois ღ says:

    idk why i felt the need to watch this after i just took my SAT today

  11. Hydersun fearless says:

    The people who disliked this video are the ones who feel jealous of her teaching style

  12. Hydersun fearless says:

    Omg your blue eyes..

  13. DEBSARATHI SEN says:

    you call this fast u could have solved the first question in 5s just write 8 as 2^3 and divide

  14. Yuvraj Swayam says:

    Fastest way to solve this is to take y=0 and then your x will be x=4 just put the value of Y and X you will get 8^4 which is equal to 2^12

  15. Fijigoya 123 says:

    She also could have changed 8^x to 2^3x off the bat and then you have 2^(3x-y) and we know that 3x-y=12

  16. Muhammad Memon says:

    This didn’t help at all

  17. Eyüp says:

    Could you please explain where is the "hard" questions? We solve these questions to win a good high-school while we're 14 years-old

  18. marilla c says:

    You made example 1 so much more difficult and harder to understand then it had to be. On the SAT that would take 2-3 minutes tops, when you can get it done in 15 seconds.

  19. Vibhuti Kushwaha says:

    damn i calculated the first question on 30 secs

    maybe i am gawd

  20. Kamal Gurbanov says:

    In 14 question there is more fast way to do this you just make them same basis and tha is all

  21. Adam El ATIFI says:

    Cnt you just use the simple rule of cos(π/2 – x) is equale to sin(x)

  22. Jay Brown says:

    Wait so what is the answer pls

  23. Deborah Solomon says:

    cah soh toa
    if you read that fast it would mean break yourself in french (casse toi)

  24. iZAP Math says:

    Students are under a lot of pressure during SAT. Good luck guys!

  25. Dhruv Tiwari says:

    Hey how this is hard questions??
    It's super easy.

  26. genc saracaydin says:

    Wellllll, you didn't need to get in to substitute values at the sart of the question 1 (or 14 according to the test) you could have just expanded 8 as 2^3 and 8^x would be 2^3x and since the bases are same now you can just substract the exponent wich leaves you with 2^3x-y. 3x-y is already given in the question to be 12 so the answer is 2^12. NOTE: You essentially did the same thing but you tried to write y in terms of x which in my opinion was a bit waste of time. But you do great videos, keep up the work!

  27. ALPHA GAMER says:

    Ok I am a 9th grader, and she makes it look so easy and when you try it it is hard.

  28. Татьяна Белоусова says:

    The first equation can be solved easier

  29. Dhia Religio says:

    god damn if living in us isn't so expensive, I'd book a plane rn and move from Indonesia

  30. Ishan Anchit says:

    Really can’t understand how any of these qualify as hard

  31. Ragad Awad says:

    U speak aloot

  32. Gurnoor Singh says:

    Can anyone tell me for which graders these problems are? I am not from USA

  33. Philosophy_paradox realityking says:

    7:21 she circles "opposite" instead of "adjacent" why?

  34. J-matics says:

    Opinion: SAT full length math doesn't have hard question

  35. Mykyta Krystolov says:

    Anyone else taking the SAT?

  36. samandar says:

    I have SAT test in December

  37. Random Cuboid says:

    They teach us these kinda problems in 8th grade

  38. Anas Idriese says:


  39. Victoria Kong says:

    I don't know if I should know how to do this in grade 10

  40. Danial Syed says:

    For question 19 sin x = cos(90-x)

  41. Shreya Pattnaik says:

    both of these questions are so so easy, i did them in less than a minute. i need a tutorial on some real hard questions.

  42. Daniel Lu says:

    there is an easier method for the first problem

    8^x/2^y = 2^3x/2^y = 2^(3x-y)

    since 3x-y=12, we have 2^12

  43. Daniel Lu says:

    lol the first problem is so easy XD ( i did this in 10 seconds)

    obviously 2^12

  44. _Hypnotize_ says:

    Wait at 4:08 how did the numberator 8 (x) became 2 (3)x or 2 (cubed x)

  45. Ryan Yang says:

    anyone taking the test tm on Nov 7th?

  46. Hasnain Bharmal says:

    These were easy

  47. CJ says:

    If you applied the exponent rule first you would get 2^3x-y and we already know 3x-y=12 so 2^12

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