## SAT® Math: Hard Questions EASY Hacks

The Best ACT® Math Books Ever are LIVE on Amazon.com now! Links below

Book 1: Algebra: https://amzn.to/2T47IIR

Book 2: Numbers, Stats, Trig & Geometry https://amzn.to/2u5iXH2

Our SAT® course is out! Start prepping with Brooke today!

Need to prep for the ACT® instead?

SUBSCRIBE NOW! And give us a thumbs up if you liked this video.

Subscribe to our mailing list!!

Learn more about SupertutorTV and all our test prep solutions at: https://supertutortv.com

Get more tips and tricks by following us!

https://www.facebook.com/supertutortv

Tweets by SupertutorTV

https://www.quora.com/profile/Brooke-Hanson-3

Learning Made Awesome!

Interested in private tutoring from a perfect scoring test prep expert? Check out http://www.brookehansontutoring.com or https://supertutortv.com/tutoring-information/ for more information!

Music:

Bright Wish by Kevin MacLeod is licensed under a Creative Commons Attribution license (https://creativecommons.org/licenses/by/4.0/)

Source: http://incompetech.com/music/royalty-free/index.html?isrc=USUAN1100377

Artist: http://incompetech.com/

Disclaimer: SAT® is a trademark registered by the College Board, which is not affiliated with, and does not endorse, this product.

algebra tutors,SAT,ACT,Brooke,Brooke Hanson,Hanson,prep,SAT prep,ACT prep,college,harvard,princeton,yale,supertutortv,tv,super tutor,admissions,high school,learning,tutor,tutoring

algebratutors.org

Should I be worried if I can’t understand 19 when I haven’t been through trigonometry yet?

For indians its 6th standard

what a joke. The SAT questions are easy, 15 year old students from other parts of the world(for instance, Britain or India) can do this without difficulty. Its more of test taking technique than knowledge of the subject tested(typical American education system).

Would you recommend buying the ACT math book to study for SAT Math?

Very useful tricks

you made the questions look way harder than it should

Good luck for tomorrow

The first one has a much easier solution (which is mentioned for half a second on the video):

Just make the bases the same FROM THE BEGINNING. So 8^x/2^x becomes 2^3x/2^y and then use the rule shown, so it becomes 2^(3x-y) and you can see that you have 3x-y=12, so the answer is 2¹²

The exponent question was done poorly in my opinion. Reducing 8^x/2^y is 2^3x/2^y, and by knowing basic exponent rules you the exponent of 2 equal to the quotient is 3x-y, which we know is 12

idk why i felt the need to watch this after i just took my SAT today

The people who disliked this video are the ones who feel jealous of her teaching style

Omg your blue eyes..

you call this fast u could have solved the first question in 5s just write 8 as 2^3 and divide

Fastest way to solve this is to take y=0 and then your x will be x=4 just put the value of Y and X you will get 8^4 which is equal to 2^12

She also could have changed 8^x to 2^3x off the bat and then you have 2^(3x-y) and we know that 3x-y=12

This didn’t help at all

Could you please explain where is the "hard" questions? We solve these questions to win a good high-school while we're 14 years-old

You made example 1 so much more difficult and harder to understand then it had to be. On the SAT that would take 2-3 minutes tops, when you can get it done in 15 seconds.

damn i calculated the first question on 30 secs

maybe i am gawdIn 14 question there is more fast way to do this you just make them same basis and tha is all

Cnt you just use the simple rule of cos(π/2 – x) is equale to sin(x)

Wait so what is the answer pls

cah soh toa

if you read that fast it would mean break yourself in french (casse toi)

Students are under a lot of pressure during SAT. Good luck guys!

Hey how this is hard questions??

It's super easy.

Wellllll, you didn't need to get in to substitute values at the sart of the question 1 (or 14 according to the test) you could have just expanded 8 as 2^3 and 8^x would be 2^3x and since the bases are same now you can just substract the exponent wich leaves you with 2^3x-y. 3x-y is already given in the question to be 12 so the answer is 2^12. NOTE: You essentially did the same thing but you tried to write y in terms of x which in my opinion was a bit waste of time. But you do great videos, keep up the work!

Ok I am a 9th grader, and she makes it look so easy and when you try it it is hard.

The first equation can be solved easier

god damn if living in us isn't so expensive, I'd book a plane rn and move from Indonesia

Really can’t understand how any of these qualify as hard

U speak aloot

Can anyone tell me for which graders these problems are? I am not from USA

7:21 she circles "opposite" instead of "adjacent" why?

Opinion: SAT full length math doesn't have hard question

Anyone else taking the SAT?

I have SAT test in December

They teach us these kinda problems in 8th grade

I ALREADY GOT 1600/1600 BUT ONLY IN MY IMAGINATION 😂

I don't know if I should know how to do this in grade 10

For question 19 sin x = cos(90-x)

both of these questions are so so easy, i did them in less than a minute. i need a tutorial on some real hard questions.

there is an easier method for the first problem

8^x/2^y = 2^3x/2^y = 2^(3x-y)

since 3x-y=12, we have 2^12

lol the first problem is so easy XD ( i did this in 10 seconds)

obviously 2^12

Wait at 4:08 how did the numberator 8 (x) became 2 (3)x or 2 (cubed x)

anyone taking the test tm on Nov 7th?

These were easy

If you applied the exponent rule first you would get 2^3x-y and we already know 3x-y=12 so 2^12